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English Support - Software => easySoft => Thema gestartet von: hans1951 am März 15, 2023, 09:43:34 Vormittag
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Hello,
I want to count the hours of two contactor outputs and make equal aging between the two. I want to make equal aging according to the time information received from the outside (for example, 5 hours is written 5 hours, one contactor is open for 5 hours the other). In case of Q1 or Q2 closing in some alarm conditions And as an extra, for example, if q1's working hour is 51 and q2's is 21, the same aging will continue again.
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Hi hans1951!
Which software version and programming language (ST, ladder diagram or function plan) do you use?
Regards
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Hello Hans
maybe this is an solution basic for Your issue?
https://easy-forum.net/index.php?topic=8578.msg37054#msg37054 (https://easy-forum.net/index.php?topic=8578.msg37054#msg37054)
Greetz
Konni
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Hi hans1951!
Which software version and programming language (ST, ladder diagram or function plan) do you use?
Regards
I use st but iif it exists in any other programming language it will be too.
Thank You
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Hello Hans
maybe this is an solution basic for Your issue?
https://easy-forum.net/index.php?topic=8578.msg37054#msg37054 (https://easy-forum.net/index.php?topic=8578.msg37054#msg37054)
Greetz
Konni
I saw this, but here it is compared with time.It's in order from largest to smallest, I did this myself.I want pump 1 to work for 5 hours, even if pump 1 has worked for 50 hours and pump 2 for 100 hours